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H3CSE-RS-RT Sample Questions:

1. 如图所示, RAT 与 RTB , RTC , RTD 建立了 IBGP 对等体关系。 RTA 在向这三个 IBGP 对等体发布路由时候使用统一的过滤器 3001 ,通过 peer grout 实现。
为实现如上目的,管理员在 RTA 上配置如下 :
[RTA-BGP] group in as-number 100
[RTA-BGP] peer in connect-interface Loopback0
[RTA-BGP] peer 10.0.0.2 group in
[RTA-BGP] peer 10.0.0.3 group in
[RTA-BGP] peer 10.0.0.4 group in
[RTA-BGP] peer in filter-polic3001 export
则在上述配置语句中,错误的是。

A) [RTA-BGP] peer 10.0.0.2 group in [RTA-BGP] peer 10.0.0.3 group in [RTA-BGP] peer 10.0.0.4 group in
B) [RTA-BGP] peer in connect-interface Loopback0
C) [RTA-BGP] peer in filter-polic3001 export
D) [RTA-BGP] group in as-number 100

2. 如图所示。图中是一个 OSI 路由网络,则图中 RTC 和 RTE 之间的路由应该是路由。

A) Level-1
B) Level-3
C) Level-0
D) Level-2

3. 关于 NSAP 地址,下列哪些描述是正确的 ?

A) Stem ID 用于标识区域内的 IS 。在集成 IS-IS 中,建议由系统的 Router ID 或接口 MAC 地址转换而来
B) NSAP 地址包括区域地址、 Stem ID 和 NSEL 三部分
C) NSAP 相当于 IP 网络中的 IP 地址和协议号。两个系统的 NSAP 相同会引起通信异常
D) 区域地址和 Stem ID 定长, NSEL 是变长的

4. 在如图所示的拓扑中, RTA 、 RTB 上分别执行如下配置 :

[RTA] ospf 1
[RTA-ospf-1] area 1
[RTA-ospf-1-area-0.0.0.1] network 1.1.1.1 0.0.0.0
[RTA-ospf-1-area-0.0.0.1] network 10.0.0.0 0.0.0.255
[RTA-ospf-1-area-0.0.0.1] network 192.168.1.0 0.0.0.255
[RTA-ospf-1-area-0.0.0.1] network 192.168.4.0 0.0.0.255
[RTA-ospf-1-area-0.0.0.1] network 192.168.7.0 0.0.0.255
[RTA-ospf-1-area-0.0.0.1] network 192.168.8.0 0.0.0.255
[RTA-ospf-1-area-0.0.0.1] network 192.168.15.0 0.0.0.255
[RTB] ospf 1
[RTB-ospf-1] area 1
[RTB-ospf-1-area-0.0.0.1] network 10.0.0.0 0.0.0.255
[RTB-ospf-1-area-0.0.0.1] area 0
[RTB-ospf-1-area-0.0.0.1] abr-summar192.168.0.0 255.255.252.0
则 RTC 的路由表中可能存在以下哪些路由

A) 192.168.1.0/24
B) 192.168.7.0/24
C) 192.168.4.0/24
D) 192.168.0.0/23

5. 在下列的 NET 地址中,哪些是正确的 ?

A) 20.abcd.1234.00
B) 02.0017.2700.0001.0002.00
C) 10.0001.0002.0003.00
D) 06.2400.0001.0020.0300.01

Solutions: